Find the Perimeter of the figure below, composed of a rectangle and two semicircles. Round to the nearest tenths place.
To find the perimeter, we need to add up the lengths of all the sides of the figure.
The rectangle has a length of 10 units and a width of 6 units. So the two lengths of the rectangle add up to $2(10) = 20$ units, and the two widths of the rectangle add up to $2(6) = 12$ units.
The figure also contains two semicircles with a radius of 6 units. The perimeter of a circle is given by $2\pi r$, so the perimeter of one semicircle is $\pi r = \pi(6) = 6\pi$ units. The figure therefore contains two semicircles, so the perimeters of the two semicircles add up to $2(6\pi) = 12\pi$ units.
So the total perimeter of the figure is $20 + 12 + 12\pi \approx 20 + 12 + 12(3.14) \approx 44 + 37.68 \approx 81.68$.
Rounded to the nearest tenths place, the perimeter of the figure is $\boxed{81.7}$ units.