Find the Area of the figure below, composed of a rectangle and a semicircle. The radius of the circle is shown. Round to the nearest tenths place.
semicircle and length 12 and 4
To find the area of the figure, we need to find the combined area of the rectangle and the semicircle.
Area of the rectangle = length * width
Area of rectangle = 12 * 4 = 48 square units
Since the semicircle has a radius of 4, the diameter (which is equal to the width of the rectangle) is 8. So the total width of the figure is 12 + 8 = 20.
Now, the area of a semicircle is (1/2) * π * r^2, where r is the radius of the semicircle.
Area of semicircle = (1/2) * π * 4^2 = 8π square units
Adding the areas of the rectangle and semicircle, the total area of the figure is 48 + 8π ≈ 48 + 25.1 ≈ 73.1 square units.
Therefore, the area of the figure composed of a rectangle and a semicircle with a radius of 4 and lengths of 12 and 4 is approximately 73.1 square units.