Problem 4
Network Address 148.75.0.0 /26
Answer the following questions by following all necessary steps.
Address class ________________________
Default subnet mask ________________________
Custom subnet mask ________________________
Total number of subnets ________________________
Total number of host addresses ________________________
Number of usable addresses ________________________
Number of bits borrowed ________________________
What is the 2nd subnet range? ______________________
What is the subnet number for the 4th subnet? ______________________
What is the subnet broadcast address for the 8th subnet? ______________________
Assignable addresses range for the 5th subnet? ______________________
Problem 5
IP Address 10.101.25.12
255.255.255.248
Answer the following questions by following all necessary steps.
Address class ________________________
Network address ________________________
Default subnet mask ________________________
Total number of subnets ________________________
Total number of host addresses ________________________
Number of usable addresses ________________________
Number of bits borrowed ________________________
What is the 1
st subnet range? ______________________
What is the subnet number for the 4th subnet? ______________________
What is the subnet broadcast address for the 7th subnet? ______________________
Assignable addresses range for the 5th subnet? ______________________�
Problem 4:
Address class: Class B
Default subnet mask: 255.255.0.0
Custom subnet mask: 255.255.255.192
Total number of subnets: 2^6 = 64 subnets
Total number of host addresses: 2^6 - 2 = 62 host addresses
Number of usable addresses: 62
Number of bits borrowed: 6
To find the 2nd subnet range, we can calculate the range of the first subnet and then add the appropriate value.
Range of the first subnet: 148.75.0.1 - 148.75.0.62
Adding the subnet size (64 addresses), the 2nd subnet range would be: 148.75.0.65 - 148.75.0.126
To find the subnet number for the 4th subnet, we can calculate the network address for the first subnet and then add the appropriate value.
Network address of the first subnet: 148.75.0.0
Adding the subnet size (64 addresses), the subnet number for the 4th subnet would be: 148.75.0.192
To find the subnet broadcast address for the 8th subnet, we can calculate the network address for the first subnet and then add the appropriate value.
Network address of the first subnet: 148.75.0.0
Adding 7 times the subnet size (64 addresses), the subnet broadcast address for the 8th subnet would be: 148.75.0.127
To find the assignable addresses range for the 5th subnet, we can calculate the range of the first subnet and then add the appropriate value.
Range of the first subnet: 148.75.0.1 - 148.75.0.62
Adding 4 times the subnet size (64 addresses), the assignable addresses range for the 5th subnet would be: 148.75.0.193 - 148.75.0.254
Problem 5:
Address class: Class A
Network address: 10.101.25.8
Default subnet mask: 255.0.0.0
Total number of subnets: 2^3 = 8 subnets
Total number of host addresses: 2^3 - 2 = 6 host addresses
Number of usable addresses: 6
Number of bits borrowed: 3
To find the 1st subnet range, we can calculate the network address and then add the appropriate value.
Network address: 10.101.25.8
Adding the subnet size (8 addresses), the 1st subnet range would be: 10.101.25.8 - 10.101.25.15
To find the subnet number for the 4th subnet, we can calculate the network address for the first subnet and then add the appropriate value.
Network address of the first subnet: 10.101.25.8
Adding 3 times the subnet size (8 addresses), the subnet number for the 4th subnet would be: 10.101.25.24
To find the subnet broadcast address for the 7th subnet, we can calculate the network address for the first subnet and then add the appropriate value.
Network address of the first subnet: 10.101.25.8
Adding 6 times the subnet size (8 addresses), the subnet broadcast address for the 7th subnet would be: 10.101.25.55
To find the assignable addresses range for the 5th subnet, we can calculate the range of the first subnet and then add the appropriate value.
Range of the first subnet: 10.101.25.8 - 10.101.25.15
Adding 4 times the subnet size (8 addresses), the assignable addresses range for the 5th subnet would be: 10.101.25.32 - 10.101.25.39