Ten less than twice a number is equal to at most 52. What are all the possible values of the number? Inuk wrote the inequality 2x−10≤52 , where x equals the number, to help solve this problem. Solve his inequality. Use the letter x as your variable and write your x term first.
Note: You will find the option to add a >
, <
, ≥
, or ≤
symbol in the Comparison (<)
keyboard.
The inequality is 2x - 10 ≤ 52. Let's solve it:
Add 10 to both sides to isolate the variable:
2x - 10 + 10 ≤ 52 + 10
2x ≤ 62
Divide both sides by 2 to solve for x:
(2x)/2 ≤ 62/2
x ≤ 31
The possible values for the number x are all real numbers less than or equal to 31.
Note: You will find the option to add a >
, <
, ≥
, or ≤
symbol in the Comparison (<)
keyboard.
Apologies for the mistake. The correct inequality is:
2x - 10 ≤ 52.
To solve this inequality, let's follow these steps:
1. Add 10 to both sides to isolate the variable:
2x - 10 + 10 ≤ 52 + 10
2x ≤ 62
2. Divide both sides by 2 to solve for x:
(2x)/2 ≤ 62/2
x ≤ 31
The correct inequality solution is x ≤ 31, meaning that all possible values for the number x are less than or equal to 31.