Solve the system:
y=x−3
y=−x−1
Put your answer in ordered pair form: (x,y). Make sure to show all work for full credit.
To solve the system, we can set the two equations equal to each other:
x - 3 = -x - 1
Adding x to both sides, we get:
2x - 3 = -1
Adding 3 to both sides, we get:
2x = 2
Dividing both sides by 2, we get:
x = 1
Now that we have the value of x, we can substitute it into one of the equations to solve for y. Let's use the first equation:
y = 1 - 3
y = -2
Therefore, the solution to the system is (1, -2).
y=x−3
y=−x−1
---------------------- add them
2 y = 0 x - 4
y = -2
go back and get x
Apologies for the mistake. Let's solve the system correctly:
We have the equations:
y = x - 3 ...(1)
y = -x - 1 ...(2)
We can substitute equation (2) into equation (1) to eliminate y:
x - 3 = -x - 1
Adding x to both sides:
2x - 3 = -1
Adding 3 to both sides:
2x = 2
Dividing both sides by 2:
x = 1
Now, substitute the value of x back into equation (1) to find y:
y = 1 - 3
y = -2
Therefore, the solution to the system is (x, y) = (1, -2).