One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab = 72. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)

Dividing these equations gives $b^3 = 2/3$. Taking the cube root gives $b = \boxed{2/\sqrt[3]{27}}$.