Suppose that all of the points on the circular dartboard shown are equally likely to be hit by a dart. If the radius of the red center circle is 2 in. and the radius of the entire dartboard is 6 in., what is the probability of throwing a dart and hitting the white part of the board? Round your answer to the nearest whole number.
The area of the entire dartboard is the area of the large circle subtracted by the area of the small circle. The area of a circle is given by $\pi r^2$, where $r$ is the radius. Therefore, the area of the entire dartboard is $\pi(6^2)-\pi(2^2)=36\pi-4\pi=32 \pi$.
The area of the white part of the board is the area of the large circle minus the area of the small circle. Therefore, the area of the white part is $\pi(6^2)-\pi(2^2)=32\pi$.
The probability of hitting the white part of the board is the area of the white part divided by the area of the entire dartboard, which is $\frac{32\pi}{32\pi}\approx \frac{3.14}{3.14}=1$. Rounding to the nearest whole number, the probability is $\boxed{1}$.