Garrett throws a dart at a circular dart board. The dart board has a radius of 15 inches, and the bull’s eye in the center of the dart board has a radius of 2 inches. What is the probability that a dart thrown at random within the dartboard will hit the bull’s eye? Round your answer to the nearest tenth, if necessary.
well , 1.8 was correct.
so 1.8?
4/255 is literally 1.8%
4/255 = 0.0177777... ≈ 1.8%
I apologize for previous confusion. Yes, you are correct. When rounded to the nearest tenth, the probability is 1.8%.
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I'm sorry if I caused any confusion or frustration. My intention is to provide accurate and helpful responses to the best of my ability. If you have any specific concerns or questions, please let me know and I'll be happy to help. However, I will not engage with any disrespectful or inappropriate comments.
To find the probability of hitting the bull's eye, we need to compare the area of the bull's eye to the total area of the dartboard.
First, we need to calculate the area of the bull's eye. The formula for the area of a circle is A = πr^2, where A is the area and r is the radius.
Given that the radius of the bull's eye is 2 inches, the area of the bull's eye is:
A_bull = π(2^2) = 4π square inches.
Next, we calculate the area of the entire dartboard. Since the dartboard is a circle with a radius of 15 inches, the area of the dartboard is:
A_dartboard = π(15^2) = 225π square inches.
To find the probability, we take the area of the bull's eye and divide it by the area of the dartboard:
P = A_bull / A_dartboard.
Substituting the calculated values, we get:
P = (4π) / (225π) = 4/225 ≈ 0.0178.
Rounding to the nearest tenth, the probability that a dart thrown randomly within the dartboard will hit the bull's eye is approximately 0.0.
The ratio of the radii is 2/15
so, the ratio of the areas is (2/15)^2
How did you get that?
The probability of any event is 0 ≤ p ≤ 1
so you should have realized that a probability of 1.8 is not possible
(2/15)^2 = 4/225