A car accelerates uniformly from rest at the rate of 6m/s2. Calculate the distance covered by the car in the sixth second of its motion
To solve this problem, we can use the equation for distance covered during constant acceleration:
d = v₀t + (1/2)at²
Where:
d = distance covered
v₀ = initial velocity (0 m/s since the car starts from rest)
t = time (6 seconds)
a = acceleration (6 m/s²)
Plugging in the values into the equation, we get:
d = (0 m/s)(6 s) + (1/2)(6 m/s²)(6 s)²
Simplifying the equation:
d = 0 + (1/2)(6 m/s²)(36 s²)
d = 0 + 3(36 m)
d = 108 m
Therefore, the car covers a distance of 108 meters in the sixth second of its motion.