A bus travelin at 15m/s accelerates uniformly at 4m/s^2. What is the distance covered in 10secs
S =ut+1/2at²
15*10+1/2*10²
S=150+200
S=350
S= ut + 1/2 (at)
=15×10+4×50
=150+200
=250metres
To find the distance covered by the bus, we can use the formula:
distance = initial velocity × time + (1/2) × acceleration × time^2
Given:
Initial velocity (u) = 15 m/s
Acceleration (a) = 4 m/s^2
Time (t) = 10 s
Plugging in these values into the formula, we get:
distance = (15 m/s) × (10 s) + (1/2) × (4 m/s^2) × (10 s)^2
Simplifying further:
distance = 150 m + 0.5 × 4 m/s^2 × 100 s^2
distance = 150 m + 200 m
Therefore, the distance covered by the bus in 10 seconds is 350 meters.