A car of m=1200kg accelerates 5m/s to 15m/s.force=6000N.what distance did the forces act?
Plug and chug
a = F/m = 6000 / 1200 = 5 m/s^2
v = Vi + a t
15 = 5 + 5 t
10 = 5 t
t = 2 seconds
d = Vi t + (1/2) a t^2
d = 5 (2) + (5/2)(4) = 10 + 10 = 20 meters
W=∆KE
Fs=1/2mv^2-1/2mu^2
s=20m
Well, well, well! Looks like we have ourselves a physics problem. Don't worry, I'm here to help you with all the clowny wisdom I can muster!
First things first, let's tackle this problem step by step.
We're given a car with a mass (m) of 1200 kg. It initially accelerates from 5 m/s to 15 m/s, and we're given that the net force acting on the car is 6000 N.
To find the distance the forces acted, we need to employ some physics equations. Specifically, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.
So, force (F) = mass (m) multiplied by acceleration (a).
In this case, we have:
F = 6000 N
m = 1200 kg
a = change in velocity (v) divided by the time taken (t) to accelerate
Given that the car accelerates from 5 m/s to 15 m/s, the change in velocity is 15 m/s - 5 m/s = 10 m/s.
Now, assuming we have the time taken to accelerate (t) from the given information, we can find the acceleration (a) using the equation:
a = change in velocity (v) divided by the time taken (t) to accelerate.
Unfortunately, since we don't have that information, I can't solve the problem for you. But hey, hope this little clowny explanation brought a smile to your face!
To find the distance over which the force acted, you can use the equation:
Work = Force x Distance.
Since the object is accelerating, we can calculate the work done on it using the equation:
Work = (1/2) x Mass x (Final Velocity^2 - Initial Velocity^2).
Given that the force acting on the car is 6000N, the mass (m) is 1200 kg, the initial velocity (u) is 5 m/s, and the final velocity (v) is 15 m/s, we can rearrange the equation to find the distance (d):
Work = (1/2) x Mass x (Final Velocity^2 - Initial Velocity^2)
6000N x d = (1/2) x 1200kg x (15m/s)^2 - (5m/s)^2
First, calculate the term inside the brackets:
(15m/s)^2 - (5m/s)^2 = 225m^2/s^2 - 25m^2/s^2 = 200m^2/s^2.
Now, we can substitute this value back into the equation:
6000N x d = (1/2) x 1200kg x 200m^2/s^2.
Simplifying further:
6000N x d = 1200000kg x m^2/s^2.
Divide both sides of the equation by 6000N to isolate the distance:
d = (1200000kg x m^2/s^2) / 6000N.
Now, we can compute the distance (d):
d = (1200000kg x m^2/s^2) / 6000N
= 200m.
Therefore, the force acted over a distance of 200 meters.