Simon has young brother. The sum of the age of the three brother is 48 and the difference between hid age of one of his younger brother is 3 how old is simon?
Let's say Simon's age is S, the age of his first younger brother is Y, and the age of his second younger brother is Z.
According to the given information:
1. The sum of the ages of the three brothers is 48, so we can write this as an equation: S + Y + Z = 48.
2. The difference between the age of one of his younger brothers is 3, so we can write this as another equation: Y - Z = 3.
We can solve these two equations simultaneously to find the values of S, Y, and Z.
From the second equation, we can isolate Y by adding Z to both sides: Y = Z + 3.
Now we substitute this expression for Y in the first equation: S + (Z + 3) + Z = 48.
Simplifying, we get: S + 2Z + 3 = 48.
Subtracting 3 from both sides: S + 2Z = 45.
Now let's try different values of Z to find the values that satisfy this equation and the condition that the sum of the three ages is 48.
If Z = 1, we have: S + 2(1) = 45 -> S + 2 = 45 -> S = 43. But in this case, the sum of the three ages is not 48.
If Z = 2, we have: S + 2(2) = 45 -> S + 4 = 45 -> S = 41. But again, the sum of the three ages is not 48.
If Z = 3, we have: S + 2(3) = 45 -> S + 6 = 45 -> S = 39. And this time, the sum of the three ages is 45+3+39 = 48, so this solution works.
Therefore, Simon is 39 years old.