jorges brother is 4 less than 3 times his age the sum of their ages is 24 how old is jorge brother
x=7
jorges ---- x years
brother ---- 3x - 4
solve
x + 3x-4 = 24
and sub back into my definitions.
Let's assume Jorge's age is represented by the variable "x".
According to the given information, Jorge's brother's age can be represented as "3x - 4".
The sum of their ages is 24, so we can write the equation:
x + (3x - 4) = 24
Combining like terms:
4x - 4 = 24
Adding 4 to both sides of the equation:
4x = 28
Dividing both sides by 4:
x = 7
Therefore, Jorge's age is 7.
To find Jorge's brother's age, we substitute the value of x into the expression we derived earlier:
3x - 4 = 3(7) - 4 = 21 - 4 = 17
So, Jorge's brother is 17 years old.
To find out how old Jorge's brother is, we first need to establish an equation using the given information. Let's assume Jorge's age is represented by 'J' and his brother's age is represented by 'B'.
According to the problem, Jorge's brother is 4 less than 3 times Jorge's age. So, we can write the equation as:
B = 3J - 4 .......(1)
It is also mentioned that the sum of their ages is 24. Therefore, we can write another equation as:
J + B = 24 .......(2)
Now we have a system of two equations. We can solve this system by substitution or elimination to find the ages of Jorge and his brother.
Let's solve this system using the substitution method:
From equation (1), we can express 'B' in terms of 'J':
B = 3J - 4
Substituting this expression into equation (2):
J + (3J - 4) = 24
Simplifying the equation:
4J - 4 = 24
Add 4 to both sides:
4J = 28
Divide both sides by 4:
J = 7
Now, substitute the value of J back into equation (1) to find the age of Jorge's brother:
B = 3(7) - 4
B = 21 - 4
B = 17
Therefore, Jorge's brother is 17 years old.