a toy helicopter flies forward with the force of 15 n into an oncoming wind of 10n the force of gravity pulls helicopter down with a force of 5 n but the propeller is providing an upward force 10n
To calculate the net force acting on the toy helicopter, we need to consider the forces acting in the vertical and horizontal directions separately.
In the vertical direction:
- The force of gravity pulls the helicopter down with a force of 5 N.
- The propeller provides an upward force of 10 N.
Hence, the net vertical force is:
Net vertical force = Upward force (propeller) - Downward force (gravity)
= 10 N - 5 N
= 5 N (upward)
In the horizontal direction:
- The helicopter flies forward with a force of 15 N.
- The oncoming wind provides a force of 10 N in the opposite direction.
Hence, the net horizontal force is:
Net horizontal force = Forward force - Opposing force (wind)
= 15 N - 10 N
= 5 N (forward)
Therefore, the net force acting on the toy helicopter can be determined by calculating the vector sum of the vertical and horizontal forces:
Net force = √[(Net vertical force)^2 + (Net horizontal force)^2]
= √[(5)^2 + (5)^2]
= √[25 + 25]
= √50
≈ 7.07 N
Thus, the net force acting on the toy helicopter is approximately 7.07 N.