A car’s engine provides a forward force of 2000 N while the force of air resistance is 800 N in the opposite direction. With what force will the car move, and in which direction?(1 point)

Responses

1200 N forward
1200 N forward

16000 N forward
16000 N forward

1200 N backward
1200 N backward

2800 N forward

The car's engine provides a forward force of 2000 N, and the force of air resistance is 800 N in the opposite direction. To find the net force, we subtract the force of air resistance from the force provided by the engine:

Net force = 2000 N - 800 N = 1200 N

Therefore, the car will move with a force of 1200 N in the forward direction.

Two movers are attempting to push a couch up a ramp. One mover applies a force of 80 N to the right, but the force of friction between the couch and the ramp is providing a force of 110 N in the opposite direction, and the couch slides down the ramp.

At minimum, how much force will the second mover need to apply to help push the couch up the ramp?

(1 point)
Responses

110 N
110 N

30 N
30 N

80 N
80 N

31 N

To determine the minimum force the second mover needs to apply to help push the couch up the ramp, we need to find the difference between the force applied by the first mover and the force of friction opposing the motion:

Force applied by the first mover = 80 N
Force of friction = 110 N

Minimum force required by the second mover = Force applied by the first mover - Force of friction

Minimum force required = 80 N - 110 N = -30 N

The minimum force the second mover needs to apply to help push the couch up the ramp is 30 N in the opposite direction (to cancel out the frictional force).

The car will move with a force of 1200 N forward.