SUZY IS 10 YEARS OLDER THAN BILLY, AND NEXT YEAR SHE WILL BE TWICE AS OLD AS BILLY. HOW OLD IS SUZY NOW? HOW OLD IS BILLY?
S-10=B
S+1=2(B+1)
subtract the second equation from the first..
-11=-b-2
b=9
S=19
To solve the given problem, we can set up a system of equations based on the information provided.
Let's assume Billy's current age is 'B' years.
According to the problem, Suzy is 10 years older than Billy, so Suzy's current age can be expressed as 'B+10' years.
Next, we are given that next year Suzy's age will be twice as old as Billy's age. This can be written as:
(B+10) + 1 = 2 * (B + 1)
Simplifying the equation:
B + 11 = 2B + 2
Bringing 'B' terms to one side and constant terms to the other side:
B - 2B = 2 - 11
-B = -9
Multiplying both sides by (-1) to isolate 'B':
B = 9
Therefore, Billy is currently 9 years old.
To find Suzy's current age, we can substitute 'B' into the equation we derived earlier:
Suzy's current age = B + 10 = 9 + 10 = 19
Therefore, Suzy is currently 19 years old.