What are the x-intercepts of y = 2xP2P – 5x – 4? (Use the quadratic formula below to find the answer.) in fraction form
The quadratic formula states that for a quadratic equation in the form of y = ax^2 + bx + c, the x-intercepts can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, the equation is y = 2x^2 – 5x – 4. Comparing it to the quadratic form, we can see that a = 2, b = -5, and c = -4.
Plugging these values into the quadratic formula, we get:
x = (-(-5) ± √((-5)^2 - 4(2)(-4))) / (2(2))
x = (5 ± √(25 + 32)) / 4
x = (5 ± √57) / 4
So the x-intercepts of y = 2x^2 – 5x – 4 are (5 + √57)/4 and (5 - √57)/4.