What are the x-intercepts of y = 2xP2P – 5x – 4? (Use the quadratic formula below to find the answer.)
To find the x-intercepts of the given quadratic equation y = 2x^2 – 5x – 4, we need to solve for x when y equals zero.
The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 2, b = -5, and c = -4.
Plugging these values into the quadratic formula, we get:
x = (-(-5) ± √((-5)^2 - 4(2)(-4))) / (2(2))
x = (5 ± √(25 + 32)) / 4
x = (5 ± √57) / 4
So, the x-intercepts of the quadratic equation y = 2x^2 – 5x – 4 are:
x = (5 + √57) / 4
x = (5 - √57) / 4