Two ropes are identical, a wave traveling through the first rope, has a frequency of 1.5 Hz and a wavelength of 6 m what is the frequency of a wave in the second rope if it’s wavelength is 2 m
To find the frequency of the wave in the second rope, we can use the formula:
frequency = wave speed / wavelength
Since the ropes are identical, their wave speed will be the same. Therefore, we can ignore the wave speed and use the formula:
frequency1 / wavelength1 = frequency2 / wavelength2
Plugging in the values we have:
1.5 Hz / 6 m = frequency2 / 2 m
Now, we can solve for frequency2:
frequency2 = (1.5 Hz / 6 m) * 2 m
frequency2 = 0.5 Hz
Therefore, the frequency of the wave in the second rope is 0.5 Hz.