A carnival game gives variety bags as prizes. The game operator uses 100 balloons and 68 stickers to put into a certain number of bags. How many balloons and how many stickers can go in each bag if they make the greatest number of bags possible so that each bag has the same number of balloons and the same number of stickers? (1 point)O 50 balloons and 34 stickers• 17 balloons and 25 stickers• 4 balloons and 4 stickers• 25 balloons and 17 stickers
To find the greatest number of bags possible, we need to find the greatest common divisor (GCD) of the number of balloons and the number of stickers.
The GCD of 100 balloons and 68 stickers is 4.
Therefore, each bag can have 4 balloons and 4 stickers.
So the answer is:
4 balloons and 4 stickers.