A carnival game gives variety bags as prizes. The game operator uses 100 balloons and 68 stickers to put into a certain number of bags. How many balloons and how many stickers can go in each bag if they make the greatest number of bags possible so that each bag has the same number of balloons and the same number of stickers?

Question

A carnival game gives variety bags as prizes. The game operator uses 100 balloons and 68 stickers to put into a certain number of bags. How many balloons and how many stickers can go in each bag if they make the greatest number of bags possible so that each bag has the same number of balloons and the same number of stickers?

Answer 1

In these type of questions, it is usually assumed that no balloons and no stickers would be left over.

Unfortunately if 25 bags would be the answer, with 2 stickers in each bag, there would be 38 stickers left over.

So the robot tutor is wrong with its answer

The HCF of 100 and 68 is 4, so they could make 4 bags, each with
25 balloons and 17 stickers.

Answer 2

mathhelper is 100% right.

Answer 3

W math helper L bot

Answer 4

Each bag can have 4 balloons and 2 stickers. This would create 25 bags.

Answer 5

To solve this problem, we can use factors and division.

First, let's find the factors of 100 and 68:

Factors of 100: 1, 2, 4, 5, 10, 20, 25, 50, 100
Factors of 68: 1, 2, 4, 17, 34, 68

Since we want to maximize the number of bags, we need to find the greatest common factor (GCF) of 100 and 68. In this case, the GCF is 4.

Now, let's divide 100 by 4 and 68 by 4:

100 ÷ 4 = 25
68 ÷ 4 = 17

So, we can put 25 balloons and 17 stickers in each bag if we want to make the greatest number of bags possible with the given number of balloons and stickers.