what is the molarity of a 500 mL solution containing 249 g of KI?
To find the molarity, we need to first calculate the number of moles of KI present in the solution using the given mass and the molar mass of KI.
The molar mass of KI (potassium iodide) can be calculated by summing the atomic masses of its elements:
Molar mass of KI = (atomic mass of K) + (atomic mass of I)
= (39.10 g/mol) + (126.90 g/mol)
= 166.00 g/mol
Next, we can calculate the number of moles using the formula:
Number of moles = mass / molar mass
Number of moles of KI = 249 g / 166.00 g/mol
≈ 1.50 mol
Now, we can calculate the molarity using the formula:
Molarity (M) = number of moles / volume of solution in liters
The volume of solution is given in milliliters, so we need to convert it to liters by dividing by 1000:
Volume of solution = 500 mL / 1000 mL/L
= 0.500 L
Molarity (M) = 1.50 mol / 0.500 L
= 3.00 M
Therefore, the molarity of the 500 mL solution containing 249 g of KI is 3.00 M.