What is the molarity of a 500 ml solution containing 249g of KI
To find the molarity of a solution, we need to determine the number of moles of solute and the volume of the solution.
1. Calculate the number of moles of KI using its molar mass:
- The molar mass of KI is 39.10 g/mol for potassium (K) and 126.9 g/mol for iodine (I). So the total molar mass of KI is 39.10 g/mol + 126.9 g/mol = 166.0 g/mol.
- Convert the given mass of KI to moles: 249 g / 166.0 g/mol = 1.5 moles.
2. Determine the volume of the solution in liters:
- Given that the volume is 500 mL, we need to convert it to liters: 500 mL / 1000 mL/L = 0.5 L.
3. Calculate the molarity of the solution:
- Molarity (M) is defined as moles of solute per liter of solution.
- Divide the moles of KI by the volume in liters: 1.5 moles / 0.5 L = 3.0 M.
Therefore, the molarity of the 500 mL solution containing 249 g of KI is 3.0 M.
To find the molarity of a solution, you need to know the moles of solute and the volume of the solution.
First, we need to calculate the moles of KI. To do this, we'll use the formula:
moles = mass / molar mass
The molar mass of KI (potassium iodide) can be calculated by adding up the atomic masses of its constituent elements. The atomic mass of potassium (K) is 39.10 g/mol, and the atomic mass of iodine (I) is 126.90 g/mol.
So, the molar mass of KI = 39.10 g/mol + 126.90 g/mol = 166.00 g/mol
Next, we'll calculate the moles of KI:
moles of KI = 249 g / 166.00 g/mol = 1.50 mol
Now that we have the moles of KI, we can find the molarity of the solution using the formula:
Molarity (M) = moles of solute / volume of solution in liters
The volume of the solution is given as 500 ml. We need to convert it to liters by dividing by 1000:
Volume of solution = 500 ml / 1000 = 0.500 L
Finally, we can calculate the molarity:
Molarity (M) = 1.50 mol / 0.500 L = 3.00 M
So, the molarity of the 500 ml solution containing 249g of KI is 3.00 M.
moles KI = grams KI/molar mass KI = ?
M = molarity = mols KI/L solution = moles KI/0.500 L = ?