The data in the chart shows the maximum and corresponding resting heart rate of a healthy 20-year-old man.
resting: 50,60,70,80,90
maximum:162,163,166,167,170
Find the equation of the trend line. Choose the correct answer below.
A. y=0.2x-151.6
B. y=0.2x+151.6
C. y=151.6
D. y=151.6x+0.2
To find the equation of the trend line, we need to determine the slope and y-intercept.
Let's calculate the slope:
slope = (change in y) / (change in x) = (maximum - resting) / (resting)
slope = [(162 - 50) + (163 - 60) + (166 - 70) + (167 - 80) + (170 - 90)] / [50 + 60 + 70 + 80 + 90]
slope = [112 + 103 + 96 + 87 + 80] / 350
slope = 478 / 350
slope = 1.366
Now, let's calculate the y-intercept:
y-intercept = average of y - (slope * average of x)
average of y = (162 + 163 + 166 + 167 + 170) / 5 = 164.8
average of x = (50 + 60 + 70 + 80 + 90) / 5 = 70
y-intercept = 164.8 - (1.366 * 70)
y-intercept = 164.8 - 95.02
y-intercept = 69.78
Therefore, the equation of the trend line is y = 1.366x + 69.78.
None of the provided answer choices is correct.