Mrs. Rose bought a total of 60 chickens and turkeys and paid a sum of $292.80 for it. 2 days later, she sold 12 chickens and had and equal number of chickens and turkeys left. If each turkey cost $2.20 more than a chicken, how much did she pay for each turkey?
Let the number of chickens that Mrs. Rose bought be x.
Therefore, the number of turkeys she bought is 60 - x.
The total cost for the chickens is x * C, where C is the cost for each chicken.
Similarly, the total cost for the turkeys is (60 - x) * (C + $2.20), since each turkey cost $2.20 more than a chicken.
The total cost for all the chickens and turkeys is $292.80.
Therefore, x * C + (60 - x) * (C + $2.20) = $292.80.
Expanding the equation, we get xC + 60C - xC + 2.20 * (60 - x) = $292.80.
Simplifying the equation, we get 60C + 2.20 * 60 - 2.20x = $292.80.
Combining like terms, we get 60C + 132 - 2.20x = $292.80.
Subtracting $132 from both sides of the equation, we get 60C - 2.20x = $292.80 - $132.
Simplifying, we get 60C - 2.20x = $160.80.
Dividing both sides of the equation by 2.20, we get 27.27C - x = $72.72.
Adding x to both sides of the equation, we get 27.27C = x + $72.72.
The problem states that Mrs. Rose sold 12 chickens 2 days later and had an equal number of chickens and turkeys left.
Since the number of chickens left is equal to the number of turkeys left,
then x - 12 = 60 - x - 12.
Simplifying the equation, we get x - x = 60 - 12 - 12, which is 0 = 36.
This equation is not true, which means that our original assumption that the number of chickens and turkeys left is equal is incorrect.
Therefore, there must be a typo or error in the problem, since it is impossible to find the number of turkeys bought and the cost of each turkey without more information.