Determine the zeros of the quadratic function y=x2+15x+36 . (When listing the smaller zero, remember that negative values are always smaller than positive values.)(1 point) smaller zero: x= ; greater zero: x=
To find the zeros of the quadratic function y = x^2 + 15x + 36, we need to solve the equation x^2 + 15x + 36 = 0.
The equation can be factored as (x + 3)(x + 12) = 0.
Setting each factor to zero:
x + 3 = 0 gives x = -3
x + 12 = 0 gives x = -12
Therefore, the smaller zero is x = -12, and the greater zero is x = -3.