Calculate the difference (subtract) in electronegativities for each set of elements below. Use the difference to determine the type of bond that will form (Use the chart above).
Column A
1.
Nitrogen (N) and Fluorine (F) in NF3.
:
Nitrogen (N) and Fluorine (F) in NF3.
2.
Fluorine (F) and Fluorine (F) in F2.
:
Fluorine (F) and Fluorine (F) in F2.
3.
Calcium (Ca) and Chlorine (Cl). in CaCl2
:
Calcium (Ca) and Chlorine (Cl). in CaCl2
Column B
a.The electronegativity difference is 1. The bond will be polar covalent.
b.The electronegativity difference is 0. The bond will be nonpolar covalent.
c.The electronegativity difference is 1. The bond will be nonpolar covalent.
d.The electronegativity difference is 2.0. The bond will be ionic.
e.The electronegativity difference is 0. The bond will be ionic.
f.The electronegativity difference is 2.0. The bond will be polar covalent.
1. The electronegativity difference between Nitrogen (N) and Fluorine (F) in NF3 is 0.9. The bond will be polar covalent. (a)
2. The electronegativity difference between Fluorine (F) and Fluorine (F) in F2 is 0. The bond will be nonpolar covalent. (b)
3. The electronegativity difference between Calcium (Ca) and Chlorine (Cl) in CaCl2 is 1.3. The bond will be polar covalent. (a)