determine the zeros of the function y = 6x^2 + 13x + 5.
To determine the zeros of the function, we set y = 0 and solve for x.
0 = 6x^2 + 13x + 5
Using the quadratic formula, x = (-b ± √(b^2 - 4ac))/(2a), where a = 6, b = 13, and c = 5, we have:
x = (-13 ± √((13)^2 - 4(6)(5)))/2(6)
x = (-13 ± √(169 - 120))/12
x = (-13 ± √49)/12
x = (-13 ± 7)/12
Therefore, the zeros of the function y = 6x^2 + 13x + 5 are:
x = (-13 + 7)/12 = -1/2
x = (-13 - 7)/12 = -5/3