A line has slope - 5/3. Through which two points could this line pass?
To find two points through which a line with a given slope passes, we need to consider that the slope-intercept form of a linear equation is y = mx + b, where m is the slope.
Let's choose an arbitrary value for b and solve for two points.
Let b = 0:
y = (-5/3)x + 0
y = (-5/3)x
For x = 0, we have y = (-5/3)(0) = 0
This gives us the point (0, 0).
For x = 3, we have y = (-5/3)(3) = -5
This gives us the point (3, -5).
Thus, the line with a slope of -5/3 could pass through the points (0, 0) and (3, -5).