A line has a slope of -3/5. Through which two points could the line pass?
Let's assume that the two points are (x1, y1) and (x2, y2).
We know that the slope of a line passing through two points can be calculated using the formula:
slope = (y2 - y1) / (x2 - x1)
Given that the slope is -3/5, we set it equal to the formula:
-3/5 = (y2 - y1) / (x2 - x1)
We can start by assuming values for x1 and y1 that make the equation easier to solve. Let's assume that x1 = 0 and y1 = 0. Plugging these values into the equation, we get:
-3/5 = (y2 - 0) / (x2 - 0)
-3/5 = y2 / x2
Now, let's rearrange the equation to solve for y2:
y2 = (-3/5) * x2
Now, we can choose a value for x2 and calculate the corresponding value of y2. Let's choose x2 = 5:
y2 = (-3/5) * 5
y2 = -3
So, one possible set of points is (0, 0) and (5, -3).
We can repeat this process with different values of x1 and y1 to find other possible sets of points that the line passes through.