A pastry chel is creating a chocolate dessert in the shape of a triangular pyramid. The pyramid has a base of 5 in, the height of the base is 4.3 in, and the slant height is 6 in. Use the correct formula to find the surface area of the chooclate pyramid (1 point)
038.25 In
O 55.75 ln^ 3
52.25 ln.^ 2
47.25 ln^ 2
To find the surface area of the chocolate pyramid, we need to find the area of the base and the area of the four triangular faces.
The area of the base can be found using the formula for the area of a triangle: A = (1/2)bh, where b is the length of the base and h is the height of the base.
Area of the base = (1/2)(5)(4.3) = 10.75 in^2
The area of each triangular face can be found using the formula for the area of a triangle: A = (1/2)bh, where b is the length of the base of the triangle (which is the slant height of the pyramid) and h is the height of the triangle (which is the height of the base).
Area of each triangular face = (1/2)(6)(4.3) = 12.9 in^2
Since there are four triangular faces, the total area of the triangular faces is 4 * 12.9 = 51.6 in^2
Therefore, the total surface area of the chocolate pyramid is the sum of the area of the base and the area of the triangular faces:
Total surface area = Area of the base + Area of the triangular faces
Total surface area = 10.75 + 51.6 = 62.35 in^2
The correct answer is not provided in the options given.