A lawn care store makes a profit of $89.00 for every push mower sold and $236.00 for every riding lawn mower sold. The owner would like to make at least $621.00 a day from the sales of push and riding lawn mowers. Let x = the number of push mowers sold. Let y = the number of riding mowers sold. Which of the following is a list of 3 possible solutions to the graph?
We are given that the store makes a profit of $89.00 for every push mower sold and $236.00 for every riding lawn mower sold. Let x be the number of push mowers sold and y be the number of riding mowers sold.
The daily profit from the sales of push mowers is given by 89x, and the daily profit from the sales of riding mowers is given by 236y. The total daily profit from both types of mowers is given by the equation:
89x + 236y = 621
To find three possible solutions to this equation, we can select values for x and y that satisfy the equation. Here are three examples:
Solution 1: Let x = 1 and y = 2
Substituting these values into the equation:
89(1) + 236(2) = 89 + 472 = 561
Solution 2: Let x = 3 and y = 0
Substituting these values into the equation:
89(3) + 236(0) = 267 + 0 = 267
Solution 3: Let x = 0 and y = 3
Substituting these values into the equation:
89(0) + 236(3) = 0 + 708 = 708
Therefore, three possible solutions to the equation are: (1, 2), (3, 0), and (0, 3).