A lawn care store makes a profit of $89 for every push mower sold and $236 for every riding lawn mower sold the owner would like to make at least $621 a day from the sale of the push mower and riding lawn mowers let x equal the number of push mowers sold and let y equal the number of riding lawn mower sold which of the following is a list of three possible solutions to the graph
To find three possible solutions to the graph, we need to determine the values of x and y that satisfy the given conditions.
First, we can set up the inequality for the daily profit:
89x + 236y ≥ 621
Now we can find three possible solutions by selecting specific values of x and y that satisfy the inequality. Here are three possible solutions:
Solution 1: x = 3, y = 2
Taking x = 3 and y = 2, the equation becomes:
89(3) + 236(2) = 267 + 472 = 739, which is greater than 621.
Solution 2: x = 5, y = 1
Taking x = 5 and y = 1, the equation becomes:
89(5) + 236(1) = 445 + 236 = 681, which is greater than 621.
Solution 3: x = 4, y = 3
Taking x = 4 and y = 3, the equation becomes:
89(4) + 236(3) = 356 + 708 = 1064, which is greater than 621.
Therefore, three possible solutions to the graph are (3, 2), (5, 1), and (4, 3).