A lawn care store makes a profit of $89.00 for every push mower sold and $236.00 for every riding lawn mower sold. The owner would like to make at least $621.00 a day from the sales of push and riding lawn mowers. Let x = the number of push mowers sold. Let y = the number of riding mowers sold. Which of the following is a list of 3 possible solutions to the graph?(1 point)
Responses
(3,1), (4,2), (1,1)
(3,1), (4,2), (1,1)
(1,2), (2,2), (3,1)
(1,2), (2,2), (3,1)
(3,2), (2,3), (1,4)
(3,2), (2,3), (1,4)
(2,1), (2,2), (2,3)
To find the possible solutions to the graph, we need to find the values of x and y that satisfy the equation:
89x + 236y ≥ 621
Let's test each option:
Option 1: (3,1), (4,2), (1,1)
Plugging in (3,1):
89(3) + 236(1) = 267 + 236 = 503 (not greater than 621)
Plugging in (4,2):
89(4) + 236(2) = 356 + 472 = 828 (greater than 621)
Plugging in (1,1):
89(1) + 236(1) = 89 + 236 = 325 (not greater than 621)
Option 2: (1,2), (2,2), (3,1)
Plugging in (1,2):
89(1) + 236(2) = 89 + 472 = 561 (not greater than 621)
Plugging in (2,2):
89(2) + 236(2) = 178 + 472 = 650 (greater than 621)
Plugging in (3,1):
89(3) + 236(1) = 267 + 236 = 503 (not greater than 621)
Option 3: (3,2), (2,3), (1,4)
Plugging in (3,2):
89(3) + 236(2) = 267 + 472 = 739 (greater than 621)
Plugging in (2,3):
89(2) + 236(3) = 178 + 708 = 886 (greater than 621)
Plugging in (1,4):
89(1) + 236(4) = 89 + 944 = 1033 (greater than 621)
Option 4: (2,1), (2,2), (2,3)
Plugging in (2,1):
89(2) + 236(1) = 178 + 236 = 414 (not greater than 621)
Plugging in (2,2):
89(2) + 236(2) = 178 + 472 = 650 (greater than 621)
Plugging in (2,3):
89(2) + 236(3) = 178 + 708 = 886 (greater than 621)
Therefore, the list of 3 possible solutions to the graph is option 3: (3,2), (2,3), (1,4)