A single die is rolled twice. The 36 equally- likely outcomes are shown to the right.
Find the probability of getting a first number that is greater than the second number
To solve this problem, we need to count the number of outcomes where the first number is greater than the second number and divide it by the total number of outcomes.
From the given list, the outcomes where the first number is greater than the second number are: (2, 1), (3, 1), (4, 1), (4, 2), (5, 1), (5, 2), (5, 3), (6, 1), (6, 2), (6, 3), (6, 4).
Counting these outcomes, we find that there are 11 outcomes where the first number is greater than the second number.
Since there are a total of 36 equally likely outcomes, the probability of getting a first number that is greater than the second number is 11/36.
Therefore, the probability of getting a first number that is greater than the second number is 11/36.