Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)
Responses
Book B will require less wrapping paper because its surface area is 0.5 in.2
less than the surface area of Book A.
Book B will require less wrapping paper because its surface area is 0.5 in.2
less than the surface area of Book A.
Book A will require less wrapping paper because its surface area is 32.75 in.2
less than the surface area of Book B.
Book A will require less wrapping paper because its surface area is 32.75 in.2
less than the surface area of Book B.
Book B will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book A.
Book B will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book A.
Book A will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book B.
To calculate the surface area of each book, we need to find the area of each side and add them together.
For Book A:
Side 1: Length * Width = 6.5 in * 1 in = 6.5 in^2
Side 2: Length * Height = 6.5 in * 8.5 in = 55.25 in^2
Side 3: Width * Height = 1 in * 8.5 in = 8.5 in^2
Total surface area of Book A: 6.5 in^2 + 55.25 in^2 + 8.5 in^2 = 70.25 in^2
For Book B:
Side 1: Length * Width = 5.5 in * 2 in = 11 in^2
Side 2: Length * Height = 5.5 in * 8 in = 44 in^2
Side 3: Width * Height = 2 in * 8 in = 16 in^2
Total surface area of Book B: 11 in^2 + 44 in^2 + 16 in^2 = 71 in^2
Therefore, Book A will require less wrapping paper because its surface area is 32.75 in^2 less than the surface area of Book B.