a resort is building a scuba diving lagoon in the shape of a upside down pyramid the top of the lagoon is a rectangle 50 feet by 20 feet and the deepest point of 25 feet deep how much water does the lagoon hold
8,333.33 ft
75,000 ft
95 ft
25,000 ft
To find the volume of the lagoon, we need to calculate the volume of the rectangular part at the top and the volume of the pyramid-shaped part below.
Volume of the rectangular part at the top:
Since it is a rectangle, the volume is given by the formula: length * width * depth.
Volume = 50 ft * 20 ft * 25 ft = 25,000 ft³
Volume of the pyramid-shaped part below:
The pyramid has a rectangular base with dimensions of 50 ft by 20 ft. The height of the pyramid is 25 ft.
The volume of a pyramid is given by the formula: (1/3) * base area * height.
Base area = length * width = 50 ft * 20 ft = 1000 ft²
Volume = (1/3) * 1000 ft² * 25 ft = 8,333.33 ft³
Total volume = volume of the rectangular part + volume of the pyramid-shaped part
Total volume = 25,000 ft³ + 8,333.33 ft³ = 33,333.33 ft³
Therefore, the lagoon can hold approximately 33,333.33 ft³ of water.