A resort is building a scuba diving lagoon in the shape of an upside down pyramid. The top of the lagoon is a rectangle that is 50 feet by 20 feet, and the deepest point of the lagoon is in the middle at 25 feet deep. How much water does the lagoon hold?(1 point)
Responses
8,333.33 ft.3
8,333.33 feet cubed
95 ft.3
95 feet cubed
75,000 ft.3
75,000 feet cubed
25,000 ft.3
Bot this is wrong chosse one of the given answers
choose
25,000 ft^3
8,333.333 ft^3
75,000 ft^3
95 ft^3
To calculate the volume of the lagoon, we need to find the volume of each section and then add them together.
First, let's find the volume of the rectangular top section of the lagoon.
Volume of rectangular top section = length * width * depth
= 50 ft * 20 ft * 25 ft
= 25,000 ft^3
Next, let's calculate the volume of the middle section.
Volume of middle section = area of base * height
= (50 ft * 20 ft) * (25 ft / 2)
= 25,000 ft^3
Finally, we add the volumes of both sections to find the total volume of the lagoon.
Total volume = volume of rectangular top section + volume of middle section
= 25,000 ft^3 + 25,000 ft^3
= 50,000 ft^3
Therefore, the lagoon holds 50,000 ft^3 of water.