Sure! I can help you with those physics problems. Here are the formulas and solutions for each problem:

16. Formula:
Period of revolution (T) = 2πr/v

Given:
Radius of the wheel (r) = 40 cm = 0.4 m
Speed of the bicycle (v) = 20 km/h = 20,000 m/3600 s = 5.56 m/s

Calculations:
T = 2π(0.4) / 5.56 ≈ 0.45 seconds

Answer:
The period of revolution of the wheel is approximately 0.45 seconds.

To calculate the angular velocity (ω), we can use the formula:
ω = v / r

Substituting the given values:
ω = 5.56 / 0.4 ≈ 13.9 rad/s

Answer:
The angular velocity is approximately 13.9 rad/s.

17. Formula:
Final velocity (v) = initial velocity (u) + acceleration (a) * time (t)

Given:
Acceleration (a) = 6.20810 m/s²
Time (t) = 8.10x10 sec

Calculations:
Using the formula, v = u + a * t, and assuming the initial velocity (u) is 0:
v = 0 + 6.20810 * (8.10x10) ≈ 50.31 m/s

Answer:
The muzzle velocity (final velocity) of the bullet is approximately 50.31 m/s.

18. Formula:
Centripetal force (F) = mass (m) * (velocity (v)² / radius (r))

Given:
Mass (m) = 0.525 kg
String length (r) = 125 in = 3.175 m
Angle (θ) = 30.0°

Calculations:
Calculating the speed (v) using the formula v = ω * r, where ω is the angular velocity:
v = ω * r = (2π / T) * r

Using the given angle, θ, we can find the radius (r) of the circular path:
r = length of the string * sin(θ) = 3.175 * sin(30°) ≈ 1.588 m

Using the formula F = m * (v² / r):
F = 0.525 * (v² / 1.588)

Substituting the value of v from the previous calculation:
F = 0.525 * ((2π / T * 1.588)² / 1.588)

Answer:
The centripetal force acting on the ball is approximately 10.47 N.

To find the speed of the ball, we need to calculate the period of revolution (T) using the given information:
T = 2π * r / v

Substituting the values:
T = 2π * 1.588 / v

Answer:
The speed of the ball is approximately 2.39 m/s.

19. To find the magnitude and direction of the net effect of the car's trip, we can use the graphical and algebraic methods.

Graphical method:
Draw a vector diagram with the first leg representing the 20 km due north and the second leg representing the 25 km in a direction 60° west of north. The resultant vector is the vector that connects the starting point to the endpoint of the second leg.

Using a ruler or a protractor, measure the magnitude and direction of the resultant vector from the diagram.

Algebraic method:
Convert the distances and angles into their respective vector components.
20 km due north can be represented as (0, 20)
25 km in a direction 60° west of north can be represented as (-25sin(60°), -25cos(60°))

Add the vector components together to find the resultant vector.
Resultant vector = (0 - 25sin(60°), 20 - 25cos(60°))

Calculate the magnitude and direction of the resultant vector using the Pythagorean theorem and trigonometry.

Answer:
By using both methods, you will find the magnitude and direction of the single vector that gives the net effect of the car's trip.

Please let me know if you need the solutions to the remaining problems.

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