Question Which equation has a graph perpendicular to the graph of 7x = 14y – 8 ? (1 point) Responses y = –2x – 7 y = –2 x – 7 y = –x + 4 y = – Image with alt text: one-half x + 4 y = x + 1 y = Image with alt text: one-half x + 1 y = 2x + 9
To find an equation that is perpendicular to the graph of 7x = 14y – 8, we need to determine the slope of the given equation. We can rewrite the equation in slope-intercept form (y = mx + b) to easily identify the slope.
7x = 14y – 8
14y = 7x + 8
y = (7/14)x + 8/14
y = (1/2)x + (4/7)
The slope of this equation is 1/2.
Perpendicular lines have slopes that are negative reciprocals of each other. Therefore, the slope of the desired equation will be -2.
Out of the given options, the equation that has a slope of -2 is y = -2x - 7.
Therefore, the correct equation is y = -2x - 7.