Which equation has a graph perpendicular to the graph of 7x = 14y – 8 ?

(1 point)
Responses

y = –2x – 7
y = –2 x – 7

y = –one-halfx + 4
y = – Image with alt text: one-half x + 4

y = one-halfx + 1
y = Image with alt text: one-half x + 1

y = 2x + 9

The equation that has a graph perpendicular to the graph of 7x = 14y – 8 is y = –one-halfx + 4.