If a triangle with vertices (4, 3), (8, 3), and (7,5) is translated to the right 4 units and down 2 units, what are the vertices of the translated figure
To translate a figure (in this case a triangle) to the right 4 units and down 2 units, we add 4 to the x-coordinates and subtract 2 from the y-coordinates of each vertex.
The original triangle has vertices:
A(4, 3)
B(8, 3)
C(7, 5)
To translate it, we add 4 to the x-coordinates and subtract 2 from the y-coordinates:
A'(4 + 4, 3 - 2) = A'(8, 1)
B'(8 + 4, 3 - 2) = B'(12, 1)
C'(7 + 4, 5 - 2) = C'(11, 3)
Therefore, the vertices of the translated triangle are:
A'(8, 1)
B'(12, 1)
C'(11, 3)