A line has a slope of-3/5 . Through which two points could this line pass? Responses (-4, -1) and (3, 20) (-4, -1) and (3, 20) (-16, -4) and (12, 8) (-16, -4) and (12, 8) (8, 1) and (13, 4) (8, 1) and (13, 4) (-5, 9) and (10, 0)
To find which points the line passes through, we need to check if the slope between the two points is equal to -3/5.
Let's check the slope between the points (-4, -1) and (3, 20):
slope = (change in y)/(change in x) = (20 - (-1))/(3 - (-4)) = (20 + 1)/(3 + 4) = 21/7 = 3/1 = 3
The slope between these two points is not equal to -3/5, so this is not a valid pair of points.
Now let's check the slope between the points (-16, -4) and (12, 8):
slope = (change in y)/(change in x) = (8 - (-4))/(12 - (-16)) = (8 + 4)/(12 + 16) = 12/28 = 3/7
The slope between these two points is not equal to -3/5, so this is not a valid pair of points either.
Next, let's check the slope between the points (8, 1) and (13, 4):
slope = (change in y)/(change in x) = (4 - 1)/(13 - 8) = 3/5
The slope between these two points is equal to -3/5, so this is a valid pair of points.
Lastly, let's check the slope between the points (-5, 9) and (10, 0):
slope = (change in y)/(change in x) = (0 - 9)/(10 - (-5)) = (-9)/(10 + 5) = -9/15 = -3/5
The slope between these two points is equal to -3/5, so this is also a valid pair of points.
Therefore, the line with a slope of -3/5 could pass through the points (8, 1) and (13, 4), or through the points (-5, 9) and (10, 0).