To rent a certain meeting room, a college charges a reservation fee of $13 and an additional fee of $5 per hour. The chemistry club wants to spend less than $68 on renting the room. What are the possible numbers of hours the chemistry club could rent the meeting room?
Use t for the number of hours.
Write your answer as an inequality solved for t.
The total cost of renting the meeting room can be represented by the equation:
Cost = Reservation fee + Additional fee per hour
We are given that the reservation fee is $13 and the additional fee per hour is $5. Therefore, the equation becomes:
Cost = $13 + $5t
We want to find the possible numbers of hours (t) that would result in a cost less than $68.
So, we can write the inequality:
$13 + $5t < $68
Subtracting $13 from both sides of the inequality:
$5t < $68 - $13
$5t < $55
Dividing both sides of the inequality by $5:
t < 11
Therefore, the possible numbers of hours the chemistry club could rent the meeting room is any value less than 11.
The answer, in inequality form solved for t, is:
t < 11