To rent a certain meeting room, a college charges a reservation fee of $36 and an additional fee of $5.40 per hour. The math club wants to spend at most $73.80 on renting the meeting room.
What are the possible amounts of time for which they could rent the meeting room?
Use t for the number of hours the meeting room is rented, and solve your inequality for t.
Let t represent the number of hours the meeting room is rented for.
The total cost for renting the meeting room can be calculated as:
Total cost = $36 + $5.40t
Since the math club wants to spend at most $73.80 on renting the meeting room, we can write the inequality:
$36 + $5.40t ≤ $73.80
Solving for t:
$5.40t ≤ $73.80 - $36
$5.40t ≤ $37.80
t ≤ $37.80 / $5.40
t ≤ 7
Therefore, the math club could rent the meeting room for at most 7 hours in order to spend at most $73.80.