One zero of f(x) = x3 - 6x2
+ 11x - 6 is 3. What are other zeros of the function?
(1 point)
• 1 and 3
• - 1 and -2
• 1 and 2
• - 1 and 3
To find the other zeros of the function, we can use synthetic division.
Since one zero is 3, we can divide the polynomial by (x - 3).
Performing synthetic division, we get:
```
3 | 1 -6 11 -6
-3 -9 6
---------------
1 -9 2 0
```
The quotient is 1x^2 - 9x + 2.
To find the zeros of this quadratic, we can use the quadratic formula:
```
x = (-(-9) ± sqrt((-9)^2 - 4(1)(2))) / 2(1)
= (9 ± sqrt(81 - 8)) / 2
= (9 ± sqrt(73)) / 2
```
Therefore, the other zeros of the function are:
• (9 + sqrt(73)) / 2
• (9 - sqrt(73)) / 2
None of the answer choices match these zeros, so none of the given options is correct.