which of the following is a solution of x^2+14x+112=0? if necessary, round to the nearest hundredth.
a ) x= -0.24
b ) x=-4.24
c ) 4.24
d ) no solution
To find the solutions of the quadratic equation x^2 + 14x + 112 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = 14, and c = 112. Substituting these values into the formula, we have:
x = (-14 ± √(14^2 - 4(1)(112))) / (2(1))
x = (-14 ± √(196 - 448)) / 2
x = (-14 ± √(-252)) / 2
Since the value inside the square root is negative, there are no real solutions. Thus, the correct answer is:
d) no solution