A shortstop is standing in the base path between second and third base when she fields the ball.
She is 30 feet from second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball? Round your answer to the nearest tenth.
(1 point)
The distance the shortstop needs to throw the ball is the diagonal of a square with sides of length 30 feet. To find the length of the diagonal, we can use the Pythagorean theorem.
Let's call the length of the diagonal "d". We can set up the equation:
d^2 = 30^2 + 30^2
Simplifying, we get:
d^2 = 900 + 900
d^2 = 1800
Taking the square root of both sides, we get:
d = √1800
d ≈ 42.4
Therefore, the shortstop needs to throw the ball approximately 42.4 feet.