if A shortstop is standing in the base path between second base and third base when she fields the ball she is 35 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest tenth

Question

if A shortstop is standing in the base path between second base and third base when she fields the ball she is 35 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest tenth

Answer 1

To solve this problem, we can use the Pythagorean theorem. The distance between second base and third base is 90 feet because the basepath forms a right angle (as the field is square). Since the shortstop is 35 feet away from second base, she will form one side of a right triangle with those two distances as the other two sides.

Let's denote the distance the shortstop needs to throw the ball as 'x'. According to the Pythagorean theorem, we have:

x^2 = 35^2 + 90^2
x^2 = 1225 + 8100
x^2 = 9325

To find 'x', we take the square root of both sides:

x ≈ √9325
x ≈ 96.6 feet

Therefore, the shortstop needs to throw the ball approximately 96.6 feet to first base. Rounding to the nearest tenth, the answer would be approximately 96.6 feet.