The volume of a container measures 0m * m ^ 3 and contains 50 marbles. Each marble has a radius of 2 mm. Use 3.14 as an approximation for pi. How much space in the box is unused? Round your answer to the nearest tenth. (1 point) 2, 325.3m * m ^ 3; 2.9m * m ^ 3; 33.5m * m ^ 2; 1.674 * 0.7m * m ^ 3
The volume of the container can be calculated using the formula for the volume of a sphere, which is V = (4/3) * pi * r^3.
Given that the radius of each marble is 2 mm, we can convert it to meters by dividing by 1000: 2 mm / 1000 = 0.002 m.
Substituting the values into the formula, we have V = (4/3) * 3.14 * (0.002)^3.
Calculating this, we get V = (4/3) * 3.14 * 0.000008 = 0.00003349 m^3.
Since the given volume of the container is 0 m * m^3, we can conclude that the space in the box is fully unused.
Therefore, the answer is 0 m * m^3.
Wrong
Apologies for the incorrect answer. Let's try solving it again.
The volume of the container is given as 0m * m^3, which means it has zero volume. However, it contains 50 marbles.
The formula for the volume of a sphere is V = (4/3) * pi * r^3.
Given that the radius of each marble is 2 mm, we can convert it to meters by dividing by 1000: 2 mm / 1000 = 0.002 m.
Substituting the values into the formula, we have V = (4/3) * 3.14 * (0.002)^3.
Calculating this, we get V = (4/3) * 3.14 * 0.000008 = 0.00003349 m^3 (approximately).
Since the volume of the container is zero, and we have filled it with marbles with a total volume of 0.00003349 m^3, the space in the box that is unused is equal to the volume of the container.
Therefore, the unused space in the box is approximately 0.00003349 m^3.
Pick one of the answers I have you
I apologize for the confusion. Based on the given answer choices, the correct answer is:
2.9m * m^3
That answer isn’t on there
Apologies for the confusion. Let's re-evaluate the problem.
Given that the container has a volume of 0m * m^3 and contains 50 marbles, we can find the total volume occupied by the marbles.
The formula for the volume of a sphere is V = (4/3) * pi * r^3.
Given that the radius of each marble is 2 mm, we can convert it to meters by dividing by 1000: 2 mm / 1000 = 0.002 m.
Substituting the values into the formula, we have V = (4/3) * 3.14 * (0.002)^3.
Calculating this, we get V = (4/3) * 3.14 * 0.000008 = 0.00003349 m^3 (approximately).
Therefore, the total volume occupied by the 50 marbles is approximately 0.00003349 m^3.
Since the volume of the container is given as 0m * m^3, the amount of space unused in the box is the same as the volume occupied by the marbles, which is approximately 0.00003349 m^3.
Rounded to the nearest tenth, the answer is approximately 0 m^3.
Therefore, the correct answer is none of the options given.